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17x^2+17x-1=0
a = 17; b = 17; c = -1;
Δ = b2-4ac
Δ = 172-4·17·(-1)
Δ = 357
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{357}}{2*17}=\frac{-17-\sqrt{357}}{34} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{357}}{2*17}=\frac{-17+\sqrt{357}}{34} $
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