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17x^2+7x-10=0
a = 17; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·17·(-10)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-27}{2*17}=\frac{-34}{34} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+27}{2*17}=\frac{20}{34} =10/17 $
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