17x2-19x-17=0

Solution for 17x2-19x-17=0 equation:

17x^2-19x-17=0

a = 17; b = -19; c = -17;
Δ = b2-4ac
Δ = -192-4·17·(-17)
Δ = 1517
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{1517}}{2*17}=\frac{19-\sqrt{1517}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{1517}}{2*17}=\frac{19+\sqrt{1517}}{34}
$