17x2-20x-16=0

Solution for 17x2-20x-16=0 equation:

17x^2-20x-16=0

a = 17; b = -20; c = -16;
Δ = b2-4ac
Δ = -202-4·17·(-16)
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{93}}{2*17}=\frac{20-4\sqrt{93}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{93}}{2*17}=\frac{20+4\sqrt{93}}{34}
$