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17x^2-21x+4=0
a = 17; b = -21; c = +4;
Δ = b2-4ac
Δ = -212-4·17·4
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-13}{2*17}=\frac{8}{34} =4/17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+13}{2*17}=\frac{34}{34} =1 $
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