If it's not what You are looking for type in the equation solver your own equation and let us solve it.
17x^2=12x
We move all terms to the left:
17x^2-(12x)=0
a = 17; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·17·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*17}=\frac{0}{34} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*17}=\frac{24}{34} =12/17 $
| 8-6u=2 | | 10x+14=50 | | 3x=-3= | | 3x=-3=-8 | | 2x+1+44=180 | | y/2=4.4 | | 12x-3=3x+18 | | 180=57(x+23) | | (3p+4)(3p−4)= | | n+5=7/3 | | n+5=73 | | 2u(u+4)-8u=2 | | 180=(6x+8)+(8x+10)+(78) | | 180=6x+ | | -0.01/(x/10)=-2.5758 | | 14x-25=22x-35 | | 0.01/(x/10)=2.5758 | | 3x2+4x=6 | | 14x-24=22x-35 | | 4x+5=3x-11 | | 1+1+1+1+1x0=0+9 | | 1+1+1+1+1+1+1x0=0=9 | | 5y(2(y+1)+2)=7y | | 1+1+1+1+1+1+1x0+1=0+9-8 | | 1+1+1+1+1+1+1x0+1=0=9 | | 5=z+5/3 | | -16^2+24t+7=10 | | x-1/11-7/66=1/6 | | 5(2x−12)+21= | | 5/x−7=2/x−2 | | 5x−7=2x−2 | | -16^2+24t+7=0 |