17y-20+16(2y-2)=40-12y

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Solution for 17y-20+16(2y-2)=40-12y equation: 



17y-20+16(2y-2)=40-12y

We move all terms to the left:

17y-20+16(2y-2)-(40-12y)=0

We add all the numbers together, and all the variables

17y+16(2y-2)-(-12y+40)-20=0

We multiply parentheses

17y+32y-(-12y+40)-32-20=0

We get rid of parentheses

17y+32y+12y-40-32-20=0

We add all the numbers together, and all the variables

61y-92=0

We move all terms containing y to the left, all other terms to the right

61y=92

y=92/61

y=1+31/61

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