17y-3(4-2y)=11(y-1)+12y-1

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Solution for 17y-3(4-2y)=11(y-1)+12y-1 equation: 



17y-3(4-2y)=11(y-1)+12y-1

We move all terms to the left:

17y-3(4-2y)-(11(y-1)+12y-1)=0

We add all the numbers together, and all the variables

17y-3(-2y+4)-(11(y-1)+12y-1)=0

We multiply parentheses

17y+6y-(11(y-1)+12y-1)-12=0



We calculate terms in parentheses: -(11(y-1)+12y-1), so:

11(y-1)+12y-1

We add all the numbers together, and all the variables

12y+11(y-1)-1

We multiply parentheses

12y+11y-11-1

We add all the numbers together, and all the variables

23y-12

Back to the equation:

-(23y-12)



We add all the numbers together, and all the variables

23y-(23y-12)-12=0

We get rid of parentheses

23y-23y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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