18(1/3)c=2

Solution for 18(1/3)c=2 equation:

18(1/3)c=2

We move all terms to the left:

18(1/3)c-(2)=0


Domain of the equation: 3)c!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

18(+1/3)c-2=0

We multiply parentheses

18c^2-2=0

a = 18; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·18·(-2)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*18}=\frac{-12}{36}
=-1/3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*18}=\frac{12}{36}
=1/3
$