If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
18*(2/3-(4*x)) = 0
18*(2/3-4*x) = 0
( 18 )
18 = 0
x belongs to the empty set
( 2/3-4*x )
2/3-4*x = 0 // - 2/3
-4*x = -2/3 // : -4
x = -2/3/(-4)
x = 1/6
x = 1/6
| 4cos(2x)-2sin(x)-3=0 | | 4/5*2=0 | | 63-x= | | 78-2x=63-x | | f(x)=x^4-8x^3/3 | | v+-2=16 | | 3x+5+3x-5=180 | | 14+n=-15 | | 60=7x+x^2 | | 20/48 | | 2(4q+3)=5(2q-6) | | 0=6x^2-24x+1 | | 17x+24=3 | | y=x(x+2)-3x | | 5+8=11 | | 25z+40z+16= | | 4[x-2]=10 | | 2x^2=28-1x | | v=14-(-9.81)(0.2) | | 2x-3x+4x-5+5x= | | 7x+15=9x+23 | | 0.80x+0.60(30)=0.40(45) | | 6P-2=10 | | 2x-5+10=0 | | -x+1=9x+2 | | 3.14*x^2=80 | | 48x^3=0 | | 30n+120n+1000= | | 2cosx+3cosx-2=0 | | -2(4s-4)-8=-2(6s+3)-2 | | 3.2q-4.6-2.3q=-0.1q-4.5 | | 0.12(24)+0.02x=0.06(6+x) |