18(3y+2)=14(2y+12)+0.5

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Solution for 18(3y+2)=14(2y+12)+0.5 equation: 



18(3y+2)=14(2y+12)+0.5

We move all terms to the left:

18(3y+2)-(14(2y+12)+0.5)=0

We multiply parentheses

54y-(14(2y+12)+0.5)+36=0



We calculate terms in parentheses: -(14(2y+12)+0.5), so:

14(2y+12)+0.5

We multiply parentheses

28y+168+0.5

We add all the numbers together, and all the variables

28y+168.5

Back to the equation:

-(28y+168.5)



We get rid of parentheses

54y-28y-168.5+36=0

We add all the numbers together, and all the variables

26y-132.5=0

We move all terms containing y to the left, all other terms to the right

26y=132.5

y=132.5/26

y=5+1/10.4

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