18(6x-30)=2(x+5)

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Solution for 18(6x-30)=2(x+5) equation:



18(6x-30)=2(x+5)
We move all terms to the left:
18(6x-30)-(2(x+5))=0
We multiply parentheses
108x-(2(x+5))-540=0
We calculate terms in parentheses: -(2(x+5)), so:
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
We get rid of parentheses
108x-2x-10-540=0
We add all the numbers together, and all the variables
106x-550=0
We move all terms containing x to the left, all other terms to the right
106x=550
x=550/106
x=5+10/53

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