18(6x-30)=2(x+5)

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Solution for 18(6x-30)=2(x+5) equation: 



18(6x-30)=2(x+5)

We move all terms to the left:

18(6x-30)-(2(x+5))=0

We multiply parentheses

108x-(2(x+5))-540=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We get rid of parentheses

108x-2x-10-540=0

We add all the numbers together, and all the variables

106x-550=0

We move all terms containing x to the left, all other terms to the right

106x=550

x=550/106

x=5+10/53

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