18(x+1)(x-1)=0

Solution for 18(x+1)(x-1)=0 equation:

Simplifying
18(x + 1)(x + -1) = 0

Reorder the terms:
18(1 + x)(x + -1) = 0

Reorder the terms:
18(1 + x)(-1 + x) = 0

Multiply (1 + x) * (-1 + x)
18(1(-1 + x) + x(-1 + x)) = 0
18((-1 * 1 + x * 1) + x(-1 + x)) = 0
18((-1 + 1x) + x(-1 + x)) = 0
18(-1 + 1x + (-1 * x + x * x)) = 0
18(-1 + 1x + (-1x + x2)) = 0

Combine like terms: 1x + -1x = 0
18(-1 + 0 + x2) = 0
18(-1 + x2) = 0
(-1 * 18 + x2 * 18) = 0
(-18 + 18x2) = 0

Solving
-18 + 18x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '18' to each side of the equation.
-18 + 18 + 18x2 = 0 + 18

Combine like terms: -18 + 18 = 0
0 + 18x2 = 0 + 18
18x2 = 0 + 18

Combine like terms: 0 + 18 = 18
18x2 = 18

Divide each side by '18'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}