18(x+1)=6(3x+4)-6

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Solution for 18(x+1)=6(3x+4)-6 equation: 



18(x+1)=6(3x+4)-6

We move all terms to the left:

18(x+1)-(6(3x+4)-6)=0

We multiply parentheses

18x-(6(3x+4)-6)+18=0



We calculate terms in parentheses: -(6(3x+4)-6), so:

6(3x+4)-6

We multiply parentheses

18x+24-6

We add all the numbers together, and all the variables

18x+18

Back to the equation:

-(18x+18)



We get rid of parentheses

18x-18x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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