18(x-1)=-6(3-x)+12

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Solution for 18(x-1)=-6(3-x)+12 equation: 



18(x-1)=-6(3-x)+12

We move all terms to the left:

18(x-1)-(-6(3-x)+12)=0

We add all the numbers together, and all the variables

18(x-1)-(-6(-1x+3)+12)=0

We multiply parentheses

18x-(-6(-1x+3)+12)-18=0



We calculate terms in parentheses: -(-6(-1x+3)+12), so:

-6(-1x+3)+12

We multiply parentheses

6x-18+12

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

18x-6x+6-18=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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