18(y-8)-14y=10(6y-4)

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Solution for 18(y-8)-14y=10(6y-4) equation: 



18(y-8)-14y=10(6y-4)

We move all terms to the left:

18(y-8)-14y-(10(6y-4))=0

We add all the numbers together, and all the variables

-14y+18(y-8)-(10(6y-4))=0

We multiply parentheses

-14y+18y-(10(6y-4))-144=0



We calculate terms in parentheses: -(10(6y-4)), so:

10(6y-4)

We multiply parentheses

60y-40

Back to the equation:

-(60y-40)



We add all the numbers together, and all the variables

4y-(60y-40)-144=0

We get rid of parentheses

4y-60y+40-144=0

We add all the numbers together, and all the variables

-56y-104=0

We move all terms containing y to the left, all other terms to the right

-56y=104

y=104/-56

y=-1+6/7

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