18+2b=3(b+3)+3

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Solution for 18+2b=3(b+3)+3 equation: 



18+2b=3(b+3)+3

We move all terms to the left:

18+2b-(3(b+3)+3)=0



We calculate terms in parentheses: -(3(b+3)+3), so:

3(b+3)+3

We multiply parentheses

3b+9+3

We add all the numbers together, and all the variables

3b+12

Back to the equation:

-(3b+12)



We get rid of parentheses

2b-3b-12+18=0

We add all the numbers together, and all the variables

-1b+6=0

We move all terms containing b to the left, all other terms to the right

-b=-6

b=-6/-1

b=+6

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