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18+3x-5=7x(-4-x)
We move all terms to the left:
18+3x-5-(7x(-4-x))=0
We add all the numbers together, and all the variables
3x-(7x(-1x-4))+18-5=0
We add all the numbers together, and all the variables
3x-(7x(-1x-4))+13=0
We calculate terms in parentheses: -(7x(-1x-4)), so:We get rid of parentheses
7x(-1x-4)
We multiply parentheses
-7x^2-28x
Back to the equation:
-(-7x^2-28x)
7x^2+28x+3x+13=0
We add all the numbers together, and all the variables
7x^2+31x+13=0
a = 7; b = 31; c = +13;
Δ = b2-4ac
Δ = 312-4·7·13
Δ = 597
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{597}}{2*7}=\frac{-31-\sqrt{597}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{597}}{2*7}=\frac{-31+\sqrt{597}}{14} $
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