18+5(y-2)-3y=10(2-y)

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Solution for 18+5(y-2)-3y=10(2-y) equation: 



18+5(y-2)-3y=10(2-y)

We move all terms to the left:

18+5(y-2)-3y-(10(2-y))=0

We add all the numbers together, and all the variables

5(y-2)-3y-(10(-1y+2))+18=0

We add all the numbers together, and all the variables

-3y+5(y-2)-(10(-1y+2))+18=0

We multiply parentheses

-3y+5y-(10(-1y+2))-10+18=0



We calculate terms in parentheses: -(10(-1y+2)), so:

10(-1y+2)

We multiply parentheses

-10y+20

Back to the equation:

-(-10y+20)



We add all the numbers together, and all the variables

2y-(-10y+20)+8=0

We get rid of parentheses

2y+10y-20+8=0

We add all the numbers together, and all the variables

12y-12=0

We move all terms containing y to the left, all other terms to the right

12y=12

y=12/12

y=1

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