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18+x=-3-5/6x
We move all terms to the left:
18+x-(-3-5/6x)=0
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(-5/6x-3)+18=0
We get rid of parentheses
x+5/6x+3+18=0
We multiply all the terms by the denominator
x*6x+3*6x+18*6x+5=0
Wy multiply elements
6x^2+18x+108x+5=0
We add all the numbers together, and all the variables
6x^2+126x+5=0
a = 6; b = 126; c = +5;
Δ = b2-4ac
Δ = 1262-4·6·5
Δ = 15756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15756}=\sqrt{4*3939}=\sqrt{4}*\sqrt{3939}=2\sqrt{3939}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-2\sqrt{3939}}{2*6}=\frac{-126-2\sqrt{3939}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+2\sqrt{3939}}{2*6}=\frac{-126+2\sqrt{3939}}{12} $
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