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18-(2/3)*x=6
We move all terms to the left:
18-(2/3)*x-(6)=0
Domain of the equation: 3)*x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+2/3)*x+18-6=0
We add all the numbers together, and all the variables
-(+2/3)*x+12=0
We multiply parentheses
-2x^2+12=0
a = -2; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-2)·12
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*-2}=\frac{0-4\sqrt{6}}{-4} =-\frac{4\sqrt{6}}{-4} =-\frac{\sqrt{6}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*-2}=\frac{0+4\sqrt{6}}{-4} =\frac{4\sqrt{6}}{-4} =\frac{\sqrt{6}}{-1} $
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