18-(3-2x)=3(x-5)

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Solution for 18-(3-2x)=3(x-5) equation: 



18-(3-2x)=3(x-5)

We move all terms to the left:

18-(3-2x)-(3(x-5))=0

We add all the numbers together, and all the variables

-(-2x+3)-(3(x-5))+18=0

We get rid of parentheses

2x-(3(x-5))-3+18=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

2x-(3x-15)+15=0

We get rid of parentheses

2x-3x+15+15=0

We add all the numbers together, and all the variables

-1x+30=0

We move all terms containing x to the left, all other terms to the right

-x=-30

x=-30/-1

x=+30

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