18-(n-4)=6-(3n+2)

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Solution for 18-(n-4)=6-(3n+2) equation:



18-(n-4)=6-(3n+2)
We move all terms to the left:
18-(n-4)-(6-(3n+2))=0
We get rid of parentheses
-n-(6-(3n+2))+4+18=0
We calculate terms in parentheses: -(6-(3n+2)), so:
6-(3n+2)
determiningTheFunctionDomain -(3n+2)+6
We get rid of parentheses
-3n-2+6
We add all the numbers together, and all the variables
-3n+4
Back to the equation:
-(-3n+4)
We add all the numbers together, and all the variables
-1n-(-3n+4)+22=0
We get rid of parentheses
-1n+3n-4+22=0
We add all the numbers together, and all the variables
2n+18=0
We move all terms containing n to the left, all other terms to the right
2n=-18
n=-18/2
n=-9

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