18-1/28(3y)=12-1/28(2y)

Solution for 18-1/28(3y)=12-1/28(2y) equation:

18-1/28(3y)=12-1/28(2y)

We move all terms to the left:

18-1/28(3y)-(12-1/28(2y))=0


Domain of the equation: 283y!=0

y!=0/283

y!=0

y∈R



Domain of the equation: 282y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-1/283y-(-1/282y+12)+18=0

We get rid of parentheses

-1/283y+1/282y-12+18=0

We calculate fractions


(-282y)/79806y^2+283y/79806y^2-12+18=0

We add all the numbers together, and all the variables

(-282y)/79806y^2+283y/79806y^2+6=0

We multiply all the terms by the denominator


(-282y)+283y+6*79806y^2=0

We add all the numbers together, and all the variables

283y+(-282y)+6*79806y^2=0

Wy multiply elements

478836y^2+283y+(-282y)=0

We get rid of parentheses

478836y^2+283y-282y=0

We add all the numbers together, and all the variables

478836y^2+y=0

a = 478836; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·478836·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*478836}=\frac{-2}{957672}
=-1/478836
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*478836}=\frac{0}{957672}
=0
$