18-1/5(40j+20)=-9j-6

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Solution for 18-1/5(40j+20)=-9j-6 equation: 



18-1/5(40j+20)=-9j-6

We move all terms to the left:

18-1/5(40j+20)-(-9j-6)=0



Domain of the equation: 5(40j+20)!=0

j∈R



We get rid of parentheses

-1/5(40j+20)+9j+6+18=0

We multiply all the terms by the denominator


9j*5(40j+20)+6*5(40j+20)+18*5(40j+20)-1=0

Wy multiply elements

45j^2(4+30j(4+90j(4-1=0

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