18-12i/3i

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Solution for 18-12i/3i equation: 


i in (-oo:+oo)

18-(((12*i)/3)*i) = 0

18-4*i^2 = 0

-4*i^2 = -18 // : -4

i^2 = 9/2

i^2 = 9/2 // ^ 1/2

abs(i) = (9/2)^(1/2)

i = (9/2)^(1/2) or i = -(9/2)^(1/2)

i in { (9/2)^(1/2), -(9/2)^(1/2) }

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