18-3(9-2t)=3(t-1)

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Solution for 18-3(9-2t)=3(t-1) equation: 



18-3(9-2t)=3(t-1)

We move all terms to the left:

18-3(9-2t)-(3(t-1))=0

We add all the numbers together, and all the variables

-3(-2t+9)-(3(t-1))+18=0

We multiply parentheses

6t-(3(t-1))-27+18=0



We calculate terms in parentheses: -(3(t-1)), so:

3(t-1)

We multiply parentheses

3t-3

Back to the equation:

-(3t-3)



We add all the numbers together, and all the variables

6t-(3t-3)-9=0

We get rid of parentheses

6t-3t+3-9=0

We add all the numbers together, and all the variables

3t-6=0

We move all terms containing t to the left, all other terms to the right

3t=6

t=6/3

t=2

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