18-4(x+4)=20(x+3)-31

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Solution for 18-4(x+4)=20(x+3)-31 equation: 



18-4(x+4)=20(x+3)-31

We move all terms to the left:

18-4(x+4)-(20(x+3)-31)=0

We multiply parentheses

-4x-(20(x+3)-31)-16+18=0



We calculate terms in parentheses: -(20(x+3)-31), so:

20(x+3)-31

We multiply parentheses

20x+60-31

We add all the numbers together, and all the variables

20x+29

Back to the equation:

-(20x+29)



We add all the numbers together, and all the variables

-4x-(20x+29)+2=0

We get rid of parentheses

-4x-20x-29+2=0

We add all the numbers together, and all the variables

-24x-27=0

We move all terms containing x to the left, all other terms to the right

-24x=27

x=27/-24

x=-1+1/8

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