18-5(1/n+2)=2

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Solution for 18-5(1/n+2)=2 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

18-(5*(1/n+2)) = 2 // - 2

18-(5*(1/n+2))-2 = 0

18-5*(1/n+2)-2 = 0

18-5*(n^-1+2)-2 = 0

18-5*(n^-1+2)-2 = 0

18-5*n^-1-12 = 0

6-5*n^-1 = 0

6-5*n^-1 = 0

-5*n^-1 = -6 // : -5

n^-1 = 6/5

-1 < 0

1/(n^1) = 6/5 // * n^1

1 = 6/5*n^1 // : 6/5

5/6 = n^1

n = 5/6

n = 5/6

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