18-6(9x-2)=17(x-3)+(13-x)-50

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Solution for 18-6(9x-2)=17(x-3)+(13-x)-50 equation: 



18-6(9x-2)=17(x-3)+(13-x)-50

We move all terms to the left:

18-6(9x-2)-(17(x-3)+(13-x)-50)=0

We add all the numbers together, and all the variables

-6(9x-2)-(17(x-3)+(-1x+13)-50)+18=0

We multiply parentheses

-54x-(17(x-3)+(-1x+13)-50)+12+18=0



We calculate terms in parentheses: -(17(x-3)+(-1x+13)-50), so:

17(x-3)+(-1x+13)-50

We multiply parentheses

17x+(-1x+13)-51-50

We get rid of parentheses

17x-1x+13-51-50

We add all the numbers together, and all the variables

16x-88

Back to the equation:

-(16x-88)



We add all the numbers together, and all the variables

-54x-(16x-88)+30=0

We get rid of parentheses

-54x-16x+88+30=0

We add all the numbers together, and all the variables

-70x+118=0

We move all terms containing x to the left, all other terms to the right

-70x=-118

x=-118/-70

x=1+24/35

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