18-6(9x-2)=17(x-3)+5(13-x)-50

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Solution for 18-6(9x-2)=17(x-3)+5(13-x)-50 equation: 



18-6(9x-2)=17(x-3)+5(13-x)-50

We move all terms to the left:

18-6(9x-2)-(17(x-3)+5(13-x)-50)=0

We add all the numbers together, and all the variables

-6(9x-2)-(17(x-3)+5(-1x+13)-50)+18=0

We multiply parentheses

-54x-(17(x-3)+5(-1x+13)-50)+12+18=0



We calculate terms in parentheses: -(17(x-3)+5(-1x+13)-50), so:

17(x-3)+5(-1x+13)-50

We multiply parentheses

17x-5x-51+65-50

We add all the numbers together, and all the variables

12x-36

Back to the equation:

-(12x-36)



We add all the numbers together, and all the variables

-54x-(12x-36)+30=0

We get rid of parentheses

-54x-12x+36+30=0

We add all the numbers together, and all the variables

-66x+66=0

We move all terms containing x to the left, all other terms to the right

-66x=-66

x=-66/-66

x=1

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