18-6(9x-2)=17(x-3)+5(13-x)=50

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Solution for 18-6(9x-2)=17(x-3)+5(13-x)=50 equation: 



18-6(9x-2)=17(x-3)+5(13-x)=50

We move all terms to the left:

18-6(9x-2)-(17(x-3)+5(13-x))=0

We add all the numbers together, and all the variables

-6(9x-2)-(17(x-3)+5(-1x+13))+18=0

We multiply parentheses

-54x-(17(x-3)+5(-1x+13))+12+18=0



We calculate terms in parentheses: -(17(x-3)+5(-1x+13)), so:

17(x-3)+5(-1x+13)

We multiply parentheses

17x-5x-51+65

We add all the numbers together, and all the variables

12x+14

Back to the equation:

-(12x+14)



We add all the numbers together, and all the variables

-54x-(12x+14)+30=0

We get rid of parentheses

-54x-12x-14+30=0

We add all the numbers together, and all the variables

-66x+16=0

We move all terms containing x to the left, all other terms to the right

-66x=-16

x=-16/-66

x=8/33

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