18-8q+10q=9(-q+4)+13q

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Solution for 18-8q+10q=9(-q+4)+13q equation: 



18-8q+10q=9(-q+4)+13q

We move all terms to the left:

18-8q+10q-(9(-q+4)+13q)=0

We add all the numbers together, and all the variables

-8q+10q-(9(-1q+4)+13q)+18=0

We add all the numbers together, and all the variables

2q-(9(-1q+4)+13q)+18=0



We calculate terms in parentheses: -(9(-1q+4)+13q), so:

9(-1q+4)+13q

We add all the numbers together, and all the variables

13q+9(-1q+4)

We multiply parentheses

13q-9q+36

We add all the numbers together, and all the variables

4q+36

Back to the equation:

-(4q+36)



We get rid of parentheses

2q-4q-36+18=0

We add all the numbers together, and all the variables

-2q-18=0

We move all terms containing q to the left, all other terms to the right

-2q=18

q=18/-2

q=-9

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