18-8q+10q=9(-q+4)+13q

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Solution for 18-8q+10q=9(-q+4)+13q equation:



18-8q+10q=9(-q+4)+13q
We move all terms to the left:
18-8q+10q-(9(-q+4)+13q)=0
We add all the numbers together, and all the variables
-8q+10q-(9(-1q+4)+13q)+18=0
We add all the numbers together, and all the variables
2q-(9(-1q+4)+13q)+18=0
We calculate terms in parentheses: -(9(-1q+4)+13q), so:
9(-1q+4)+13q
We add all the numbers together, and all the variables
13q+9(-1q+4)
We multiply parentheses
13q-9q+36
We add all the numbers together, and all the variables
4q+36
Back to the equation:
-(4q+36)
We get rid of parentheses
2q-4q-36+18=0
We add all the numbers together, and all the variables
-2q-18=0
We move all terms containing q to the left, all other terms to the right
-2q=18
q=18/-2
q=-9

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