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18/(x-3)=24-3x
We move all terms to the left:
18/(x-3)-(24-3x)=0
Domain of the equation: (x-3)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=3
x∈R
18/(x-3)-(-3x+24)=0
We get rid of parentheses
18/(x-3)+3x-24=0
We multiply all the terms by the denominator
3x*(x-3)-24*(x-3)+18=0
We multiply parentheses
3x^2-9x-24x+72+18=0
We add all the numbers together, and all the variables
3x^2-33x+90=0
a = 3; b = -33; c = +90;
Δ = b2-4ac
Δ = -332-4·3·90
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-3}{2*3}=\frac{30}{6} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+3}{2*3}=\frac{36}{6} =6 $
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