18/5=2(6y-12)/3y

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Solution for 18/5=2(6y-12)/3y equation: 



18/5=2(6y-12)/3y

We move all terms to the left:

18/5-(2(6y-12)/3y)=0



Domain of the equation: 3y)!=0

y!=0/1

y!=0

y∈R



We calculate fractions


(-(2(6y-12)*5)/3y*5)+54y/3y*5)=0



We calculate terms in parentheses: +(-(2(6y-12)*5)/3y*5), so:

-(2(6y-12)*5)/3y*5

We multiply all the terms by the denominator


-(2(6y-12)*5)



We calculate terms in parentheses: -(2(6y-12)*5), so:

2(6y-12)*5

We multiply parentheses

60y-120

Back to the equation:

-(60y-120)



We get rid of parentheses

-60y+120

Back to the equation:

+(-60y+120)



We get rid of parentheses

-60y+54y/3y*5)+120=0

We multiply all the terms by the denominator


-60y*3y*5)+120+54y=0

Wy multiply elements

-900y^3*5=0

We do not support eypression: y^3

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