180-1/2x=160+1/3x

Solution for 180-1/2x=160+1/3x equation:

180-1/2x=160+1/3x

We move all terms to the left:

180-1/2x-(160+1/3x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-1/2x-(1/3x+160)+180=0

We get rid of parentheses

-1/2x-1/3x-160+180=0

We calculate fractions


(-3x)/6x^2+(-2x)/6x^2-160+180=0

We add all the numbers together, and all the variables

(-3x)/6x^2+(-2x)/6x^2+20=0

We multiply all the terms by the denominator


(-3x)+(-2x)+20*6x^2=0

Wy multiply elements

120x^2+(-3x)+(-2x)=0

We get rid of parentheses

120x^2-3x-2x=0

We add all the numbers together, and all the variables

120x^2-5x=0

a = 120; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·120·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*120}=\frac{0}{240}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*120}=\frac{10}{240}
=1/24
$