180-40-(9x-2)=180-(20x+5)

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Solution for 180-40-(9x-2)=180-(20x+5) equation: 



180-40-(9x-2)=180-(20x+5)

We move all terms to the left:

180-40-(9x-2)-(180-(20x+5))=0

We add all the numbers together, and all the variables

-(9x-2)-(180-(20x+5))+140=0

We get rid of parentheses

-9x-(180-(20x+5))+2+140=0



We calculate terms in parentheses: -(180-(20x+5)), so:

180-(20x+5)

determiningTheFunctionDomain
-(20x+5)+180

We get rid of parentheses

-20x-5+180

We add all the numbers together, and all the variables

-20x+175

Back to the equation:

-(-20x+175)



We add all the numbers together, and all the variables

-9x-(-20x+175)+142=0

We get rid of parentheses

-9x+20x-175+142=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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