180-x=x+(1/4)x

Solution for 180-x=x+(1/4)x equation:

180-x=x+(1/4)x

We move all terms to the left:

180-x-(x+(1/4)x)=0


Domain of the equation: 4)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-x-(x+(+1/4)x)+180=0

We add all the numbers together, and all the variables

-1x-(x+(+1/4)x)+180=0

We multiply all the terms by the denominator


-1x*4)x)-(x+(+180*4)x)+1=0

We add all the numbers together, and all the variables

-1x*4)x)-(x+720x)+1=0

Wy multiply elements

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$