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180=(10x+8)(11x-59)
We move all terms to the left:
180-((10x+8)(11x-59))=0
We multiply parentheses ..
-((+110x^2-590x+88x-472))+180=0
We calculate terms in parentheses: -((+110x^2-590x+88x-472)), so:We get rid of parentheses
(+110x^2-590x+88x-472)
We get rid of parentheses
110x^2-590x+88x-472
We add all the numbers together, and all the variables
110x^2-502x-472
Back to the equation:
-(110x^2-502x-472)
-110x^2+502x+472+180=0
We add all the numbers together, and all the variables
-110x^2+502x+652=0
a = -110; b = 502; c = +652;
Δ = b2-4ac
Δ = 5022-4·(-110)·652
Δ = 538884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{538884}=\sqrt{36*14969}=\sqrt{36}*\sqrt{14969}=6\sqrt{14969}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(502)-6\sqrt{14969}}{2*-110}=\frac{-502-6\sqrt{14969}}{-220} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(502)+6\sqrt{14969}}{2*-110}=\frac{-502+6\sqrt{14969}}{-220} $
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