180=(2x+25)(3x)

Solution for 180=(2x+25)(3x) equation:

180=(2x+25)(3x)

We move all terms to the left:

180-((2x+25)(3x))=0


We calculate terms in parentheses: -((2x+25)3x), so:

(2x+25)3x

We multiply parentheses

6x^2+75x

Back to the equation:

-(6x^2+75x)


We get rid of parentheses

-6x^2-75x+180=0

a = -6; b = -75; c = +180;
Δ = b2-4ac
Δ = -752-4·(-6)·180
Δ = 9945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9945}=\sqrt{9*1105}=\sqrt{9}*\sqrt{1105}=3\sqrt{1105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-3\sqrt{1105}}{2*-6}=\frac{75-3\sqrt{1105}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+3\sqrt{1105}}{2*-6}=\frac{75+3\sqrt{1105}}{-12}
$