180=(2z)+(z+10)+(z+46)

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Solution for 180=(2z)+(z+10)+(z+46) equation: 



180=(2z)+(z+10)+(z+46)

We move all terms to the left:

180-((2z)+(z+10)+(z+46))=0



We calculate terms in parentheses: -(2z+(z+10)+(z+46)), so:

2z+(z+10)+(z+46)

We get rid of parentheses

2z+z+z+10+46

We add all the numbers together, and all the variables

4z+56

Back to the equation:

-(4z+56)



We get rid of parentheses

-4z-56+180=0

We add all the numbers together, and all the variables

-4z+124=0

We move all terms containing z to the left, all other terms to the right

-4z=-124

z=-124/-4

z=+31

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