180=(30+x)x

Solution for 180=(30+x)x equation:

180=(30+x)x

We move all terms to the left:

180-((30+x)x)=0

We add all the numbers together, and all the variables

-((x+30)x)+180=0


We calculate terms in parentheses: -((x+30)x), so:

(x+30)x

We multiply parentheses

x^2+30x

Back to the equation:

-(x^2+30x)


We get rid of parentheses

-x^2-30x+180=0

We add all the numbers together, and all the variables

-1x^2-30x+180=0

a = -1; b = -30; c = +180;
Δ = b2-4ac
Δ = -302-4·(-1)·180
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-18\sqrt{5}}{2*-1}=\frac{30-18\sqrt{5}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+18\sqrt{5}}{2*-1}=\frac{30+18\sqrt{5}}{-2}
$