180=(3x+28)+(5x+52)+(2x-10)

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Solution for 180=(3x+28)+(5x+52)+(2x-10) equation: 



180=(3x+28)+(5x+52)+(2x-10)

We move all terms to the left:

180-((3x+28)+(5x+52)+(2x-10))=0



We calculate terms in parentheses: -((3x+28)+(5x+52)+(2x-10)), so:

(3x+28)+(5x+52)+(2x-10)

We get rid of parentheses

3x+5x+2x+28+52-10

We add all the numbers together, and all the variables

10x+70

Back to the equation:

-(10x+70)



We get rid of parentheses

-10x-70+180=0

We add all the numbers together, and all the variables

-10x+110=0

We move all terms containing x to the left, all other terms to the right

-10x=-110

x=-110/-10

x=+11

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