180=(4x)+(2x-10)+(2x+30)

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Solution for 180=(4x)+(2x-10)+(2x+30) equation: 



180=(4x)+(2x-10)+(2x+30)

We move all terms to the left:

180-((4x)+(2x-10)+(2x+30))=0



We calculate terms in parentheses: -(4x+(2x-10)+(2x+30)), so:

4x+(2x-10)+(2x+30)

We get rid of parentheses

4x+2x+2x-10+30

We add all the numbers together, and all the variables

8x+20

Back to the equation:

-(8x+20)



We get rid of parentheses

-8x-20+180=0

We add all the numbers together, and all the variables

-8x+160=0

We move all terms containing x to the left, all other terms to the right

-8x=-160

x=-160/-8

x=+20

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