180=(6x+25)(2x+105)

Solution for 180=(6x+25)(2x+105) equation:

180=(6x+25)(2x+105)

We move all terms to the left:

180-((6x+25)(2x+105))=0

We multiply parentheses ..

-((+12x^2+630x+50x+2625))+180=0


We calculate terms in parentheses: -((+12x^2+630x+50x+2625)), so:

(+12x^2+630x+50x+2625)

We get rid of parentheses

12x^2+630x+50x+2625

We add all the numbers together, and all the variables

12x^2+680x+2625

Back to the equation:

-(12x^2+680x+2625)


We get rid of parentheses

-12x^2-680x-2625+180=0

We add all the numbers together, and all the variables

-12x^2-680x-2445=0

a = -12; b = -680; c = -2445;
Δ = b2-4ac
Δ = -6802-4·(-12)·(-2445)
Δ = 345040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{345040}=\sqrt{16*21565}=\sqrt{16}*\sqrt{21565}=4\sqrt{21565}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-680)-4\sqrt{21565}}{2*-12}=\frac{680-4\sqrt{21565}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-680)+4\sqrt{21565}}{2*-12}=\frac{680+4\sqrt{21565}}{-24}
$