180=(7x+2)+(3x-5)+(-12+5x)

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Solution for 180=(7x+2)+(3x-5)+(-12+5x) equation: 



180=(7x+2)+(3x-5)+(-12+5x)

We move all terms to the left:

180-((7x+2)+(3x-5)+(-12+5x))=0

We add all the numbers together, and all the variables

-((7x+2)+(3x-5)+(5x-12))+180=0



We calculate terms in parentheses: -((7x+2)+(3x-5)+(5x-12)), so:

(7x+2)+(3x-5)+(5x-12)

We get rid of parentheses

7x+3x+5x+2-5-12

We add all the numbers together, and all the variables

15x-15

Back to the equation:

-(15x-15)



We get rid of parentheses

-15x+15+180=0

We add all the numbers together, and all the variables

-15x+195=0

We move all terms containing x to the left, all other terms to the right

-15x=-195

x=-195/-15

x=+13

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