180=(m+8)+(2m-3)+(m+6)

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Solution for 180=(m+8)+(2m-3)+(m+6) equation:



180=(m+8)+(2m-3)+(m+6)
We move all terms to the left:
180-((m+8)+(2m-3)+(m+6))=0
We calculate terms in parentheses: -((m+8)+(2m-3)+(m+6)), so:
(m+8)+(2m-3)+(m+6)
We get rid of parentheses
m+2m+m+8-3+6
We add all the numbers together, and all the variables
4m+11
Back to the equation:
-(4m+11)
We get rid of parentheses
-4m-11+180=0
We add all the numbers together, and all the variables
-4m+169=0
We move all terms containing m to the left, all other terms to the right
-4m=-169
m=-169/-4
m=42+1/4

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