180=(m+8)+(2m-3)+(m+6)

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Solution for 180=(m+8)+(2m-3)+(m+6) equation: 



180=(m+8)+(2m-3)+(m+6)

We move all terms to the left:

180-((m+8)+(2m-3)+(m+6))=0



We calculate terms in parentheses: -((m+8)+(2m-3)+(m+6)), so:

(m+8)+(2m-3)+(m+6)

We get rid of parentheses

m+2m+m+8-3+6

We add all the numbers together, and all the variables

4m+11

Back to the equation:

-(4m+11)



We get rid of parentheses

-4m-11+180=0

We add all the numbers together, and all the variables

-4m+169=0

We move all terms containing m to the left, all other terms to the right

-4m=-169

m=-169/-4

m=42+1/4

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