180=(x)+(6x-11)+(3x)

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Solution for 180=(x)+(6x-11)+(3x) equation: 



180=(x)+(6x-11)+(3x)

We move all terms to the left:

180-((x)+(6x-11)+(3x))=0



We calculate terms in parentheses: -(x+(6x-11)+3x), so:

x+(6x-11)+3x

We add all the numbers together, and all the variables

4x+(6x-11)

We get rid of parentheses

4x+6x-11

We add all the numbers together, and all the variables

10x-11

Back to the equation:

-(10x-11)



We get rid of parentheses

-10x+11+180=0

We add all the numbers together, and all the variables

-10x+191=0

We move all terms containing x to the left, all other terms to the right

-10x=-191

x=-191/-10

x=19+1/10

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