180=(x)+(x-40)+(x-80)

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Solution for 180=(x)+(x-40)+(x-80) equation: 



180=(x)+(x-40)+(x-80)

We move all terms to the left:

180-((x)+(x-40)+(x-80))=0



We calculate terms in parentheses: -(x+(x-40)+(x-80)), so:

x+(x-40)+(x-80)

We get rid of parentheses

x+x+x-40-80

We add all the numbers together, and all the variables

3x-120

Back to the equation:

-(3x-120)



We get rid of parentheses

-3x+120+180=0

We add all the numbers together, and all the variables

-3x+300=0

We move all terms containing x to the left, all other terms to the right

-3x=-300

x=-300/-3

x=+100

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