180=(x+10)+(3x-6)+(12x+48)

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Solution for 180=(x+10)+(3x-6)+(12x+48) equation:



180=(x+10)+(3x-6)+(12x+48)
We move all terms to the left:
180-((x+10)+(3x-6)+(12x+48))=0
We calculate terms in parentheses: -((x+10)+(3x-6)+(12x+48)), so:
(x+10)+(3x-6)+(12x+48)
We get rid of parentheses
x+3x+12x+10-6+48
We add all the numbers together, and all the variables
16x+52
Back to the equation:
-(16x+52)
We get rid of parentheses
-16x-52+180=0
We add all the numbers together, and all the variables
-16x+128=0
We move all terms containing x to the left, all other terms to the right
-16x=-128
x=-128/-16
x=+8

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